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If it took 49.33 mL of 0.2454 M KOH solution to neutralize 35.0 mL of arsenic acid (H3AsO4), what is the concentration (M) of the arsenic acid solution?

If it took 49.33 mL of 0.2454 M KOH solution to neutralize 35.0 mL of arsenic acid (H3AsO4), what is the concentration (M) of the arsenic acid solution?
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If it took 49.33 mL of 0.2454 M KOH solution to neutralize 35.0 mL of arsenic acid (H3AsO4), what is the concentration (M) of the arsenic acid solution?

User Pierrick Rambaud
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1 Answer

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Answer: 49.33x 0.2454= M x 35

M: 0.35 M

Step-by-step explanation:

User Jake McGraw
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