If it took 49.33 mL of 0.2454 M KOH solution to neutralize 35.0 mL of arsenic acid (H3AsO4), what is the concentration (M) of the arsenic acid solution?

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asked Jul 28, 2023 58.9k views

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If it took 49.33 mL of 0.2454 M KOH solution to neutralize 35.0 mL of arsenic acid (H3AsO4), what is the concentration (M) of the arsenic acid solution?

Chemistry
high-school

Pierrick Rambaud asked

by Pierrick Rambaud

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Answer: 49.33x 0.2454= M x 35

M: 0.35 M

Step-by-step explanation:

Jake McGraw answered Aug 4, 2023

by Jake McGraw

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