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A line passes through the point (4, 9) and has a slope of -3/2.

Write an equation in slope-intercept form for this line.

1 Answer

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(\stackrel{x_1}{4}~,~\stackrel{y_1}{9})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{3}{2} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{- \cfrac{3}{2}}(x-\stackrel{x_1}{4}) \\\\\\ y-9=- \cfrac{3}{2}x+6\implies {\Large \begin{array}{llll} y=- \cfrac{3}{2}x+15 \end{array}}

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