Question

A ball with a weight of 15 N is thrown striaght up into the air with an initial speed of 14 m/s. What is the maximum height it will achieve above its starting position

Answer 1

10m above initial height

Step-by-step explanation:

let acceleration due to gravity = 9.8 m/s/s

v final = v initial - time • gravity

0 = 14m/s - t • 9.8m/s/s

t = 1.43 seconds to reach max height

distance = 1/2 • acceleration • time^2

distance = 1/2 • 9.8 • 1.43^2

distance = 10 meters above initial height