Answer: 240
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Step-by-step explanation:
- 1st row = 50 seats
- 2nd row = 50+10 = 60 seats
- 3rd row = 60+10 = 70 seats
and so on.
We have the arithmetic sequence 50, 60, 70, ...
= 50 = first term- d = 10 = common difference
We'll use the formula below to also plug in n = 20 to determine how many seats there are in the 20th row.
![a_n = a_1 + d(n-1)\\\\a_n = 50 + 10(n-1)\\\\a_(20) = 50 + 10(20-1)\\\\a_(20) = \boldsymbol{240}\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/x6ykj239ks6eziquw7e5c3spwjb88pw0ic.png)
There are 240 seats in the 20th row of the center section.