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Three numbers are in the ratio of 5:6:7. Find the smallest nuber if the sum is 72.

User LStrike
by
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1 Answer

3 votes

Answer:

20

Explanation:

Three numbers are in the ratio of 5:6:7. Find the smallest nuber if the sum is 72.

  1. sum the ratios
  2. divide 72 by 18 (sum of ratio)
  3. multiply by 5 (smallest ratio)
  • 5 + 6 + 7 = 18
  • 72 : 18 =
  • 4

4 × 5 = 20 (smallest number)

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check

4 × 6 = 24 (number with ratio 6)

4 × 7 = 28 (biggest number)

sum

20 + 24 + 28 = 72

The answer is good

User Lilia
by
7.9k points