Question

Experiencing a constant horizontal 1.1m / s wind, a hot-air balloon ascends from the launch site at a constant vertical speed of 2.5m / s At a height of 205 m, the balloonist maintains constant altitude for 10.0 s before releasing a small sandbag. How far from the launch site does the sandbag land ?

Answer 1

Below

Step-by-step explanation:

The balloon is moving horizontally the entire time it is in the air....after the sandbag is released , it to is moving horizontally until it hits the ground...

Balloon moves ( 205 m / 2.5 m/s + 10s ) * 1.1 m/s = 101.2 m

The sandbag takes falls 205 m

205 = 1/2 a t^2 showing it takes t= 6.46 seconds to hit the ground it travels 6.46 s * 1.1 ms = 7.1 m horizontally

101.2 + 7.1 = 108.3 m from launch site