Question

What number of moles will be produced from 11.2dm3 of NH3 at s. T. O

Answer 1

`\huge\boxed{\sf n = 0.5 \ mol}`

Step-by-step explanation:

Given Data:

Volume = v = 11.2 dm³

Molar Volume = V = 22.4 dm³/mol

Required:

Moles = n = ?

Formula:

`\displaystyle n = (v)/(V)`

Solution:

`\displaystyle n = (11.2)/(22.4) \\\\n = 0.5 \ mol\\\\\rule[225]{225}{2}`