Question

The production of silverite required combination of three metais: 1/4 Rosine, 1/5 Lomelite, and the remainder Anderte.if 800kg of silverite is to be produced.find the number of kg of each metal required​

Answer 1

Explanation:

let's just apply common sense :

1/4 is Rosine, so, 800/4 = 200 kg Rosine.

1/5 is Lomelite, so, 800/5 = 160 kg Lomelite.

that leaves 800 - 200 - 160 = 440 kg Anderte

that's really it.×

FYI - when we use fractions for everything, we would say

1/4 = 5/20 Rosine

1/5 = 4/20 Lomelite

that leaves 20/20 - 5/20 - 4/20 = (20-9)/20 = 11/20 if Anderte.