Question

Find an equation for a line passing through (10,10) that is perpendicular to the line with equation 5x + 8y = -9 Write your equation in either point-slope form or slope-intercept form.

yeah i really need help

Answer 1

Answer:
`y-10=(8)/(5)(x-10)`

Explanation:

`5x+8y=-9\\\\8y=-5x-9\\\\y=-(5)/(8)x-(9)/(8)`

Perpendicular lines have slopes that are negative reciprocals of each other, so the slope of the line we need to find is 8/5.

So, the equation is
`y-10=(8)/(5)(x-10)`.