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Section 8.1 Introduction to the Laplace Transforms

Problem 2.
Use the table of Laplace transforms to find the Laplace transforms of the following functions.

(a)cosh \: t \: sin \: t

(b) {sin}^(2) t

(c) {cos}^(2) 2t

(d) {cosh}^(2) t

(e)t \: sinh \: 2t

(f)sin \: t \: cos \: t

(g)sin(t + (\pi)/(4) )

(h)cos2t - cos3t

(i)sin2t + cos4t


Section 8.1 Introduction to the Laplace Transforms Problem 2. Use the table of Laplace-example-1
User Zalo
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1 Answer

4 votes

I don't know what table you have as reference, but I suspect it includes the following transforms:


1 \leftrightarrow \frac1s


e^(at) \leftrightarrow (1)/(s-a)


\cos(at) \leftrightarrow (s)/(s^2+a^2)


\sin(at) \leftrightarrow (a)/(s^2+a^2)


\cosh(at) \leftrigharrow (s)/(s^2-a^2)


\sinh(at) \leftrigharrow (a)/(s^2-a^2)

It probably also includes some more general properties, like


t f(t) \leftrightarrow -F'(s)


e^(at) f(t) \leftrightarrow F(s-a)

where F(s) is the Laplace transform of f(t).

Beyond these, you should also know the following identities:


\cosh(t) = \frac{e^t + e^(-t)}2


\cosh^2(t) = \frac{1 + \cosh(2t)}2


\cos^2(t) = \frac{1 + \cos(2t)}2


\sin^2(t) = \frac{1 - \cos(2t)}2


\sin(2t) = 2 \sin(t) \cos(t)


\sin(t \pm T) = \sin(t) \cos(T) \pm \cos(t) \sin(T)

Putting everything together, we have

• (a)


\cosh(t) \sin(t) = \frac{e^t + e^(-t)}2 * \sin(t) = \frac12 e^t \sin(t) + \frac12 e^(-t) \sin(t)

and the Laplace transform is


\frac12 F(s - 1) + \frac12 F(s + 1)

where F(s) is the transform of sin(t),


F(s) = (1)/(s^2 + 1)

Then


\cosh(t) \sin(t) \leftrightarrow \frac{\frac1{(s-1)^2+1} + \frac1{(s+1)^2+1}}2 = \boxed{(s^2+2)/(s^4+4)}

• (b)


\sin^2(t) = \frac12 \left(1 - \cos(2t)\right)

and the transform is


F(s) = \frac12 \left(\frac1s - (s)/(s^2+4)\right) = \boxed{(2)/(s^3+4s)}

• (c)


\cos^2(2t) = \frac12 \left(1 + \cos(4t)\right)

with transform


F(s) = \frac12 \left(\frac1s + (s)/(s^2+16)\right) = \boxed{(s^2+8)/(s^3+16s)}

• (d)


\cosh^2(t) = \frac12 \left(1 + \cosh(2t)\right)

with transform


F(s) = \frac12 \left(\frac1s + (s)/(s^2-4)\right) = \boxed{-\frac2{s^3-4s}}

• (e)


t\sinh(2t) \leftrightarrow -F'(s)

where F(s) is the Laplace transform of sinh(2t),


F(s) = (2)/(s^2 - 4) \implies -F'(s) = \boxed{(4s)/((s^2-4)^2)}

• (f)


\sin(t) \cos(t) = \frac12 \left(2\sin(t) \cos(t)\right) = \frac12 \sin(2t)

with transform


F(s) = \frac12 * (2)/(s^2+4) = \boxed{\frac1{s^2+4}}

• (g)


\sin\left(t+\frac\pi4\right) = \sin(t) \cos\left(\frac\pi4\right) + \cos(t) \sin\left(\frac\pi4\right) = \frac1{\sqrt2} \left(\sin(t) + \cos(t)\right)

with transform


F(s) = \frac1{\sqrt2} \left(\frac1{s^2+1} + (s)/(s^2+1)\right) = \boxed{(s+1)/(\sqrt2 (s^2+1))}

The last two are trivial and follow directly from the properties listed above.

• (h)


\cos(2t) - \cos(3t) \leftrightarrow (s)/(s^2+4) - (s)/(s^2+9) = \boxed{(5s)/(s^4 + 13s^2 + 36)}

• (i)


\sin(2t) + \cos(4t) \leftrightarrow \frac2{s^2+4} + (s)/(s^2+16) = \boxed{(s^3+2s^2+4s+32)/(s^4+20s^2+64)}

User Amarilys
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