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2. For a projectile fired at 0° from a height of 19.6 m, how long does it take it to hit the ground? Remember that g = -9.8 m/s2. Initial velocity of the projectile is 40 m/s. Hint: Sine of 0° is 0 and
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2. For a projectile fired at 0° from a height of 19.6 m, how long does it take it to hit the ground? Remember that g = -9.8 m/s2. Initial velocity of the projectile is 40 m/s. Hint: Sine of 0° is 0 and Cosine of 0° is 1.

User Carlosedp
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Answer:


\huge\boxed{\sf T = 0 \ s}

Step-by-step explanation:

Formula for the time of flight of projectile:


\displaystyle T=(2v_isin \theta)/(g)

Given that, θ = 0

So,

sin 0 = 0


\displaystyle T=(2v_i(0))/(g) \\\\T = (0)/(g) \\\\T = 0 \ s\\\\\rule[225]{225}{2}

User Kevin Vaughan
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