Question

2. For a projectile fired at 0° from a height of 19.6 m, how long does it take it to hit the ground? Remember that g = -9.8 m/s2. Initial velocity of the projectile is 40 m/s. Hint: Sine of 0° is 0 and Cosine of 0° is 1.

Answer 1

`\huge\boxed{\sf T = 0 \ s}`

Step-by-step explanation:

Formula for the time of flight of projectile:

`\displaystyle T=(2v_isin \theta)/(g)`

Given that, θ = 0

So,

sin 0 = 0

`\displaystyle T=(2v_i(0))/(g) \\\\T = (0)/(g) \\\\T = 0 \ s\\\\\rule[225]{225}{2}`