Question

The sum of two numbers is 66. Two times the lesser number is 15 more than the greater number. What are the numbers

If x is a lesser number, the equation is

Answer 1

The lesser number is 27 and the greater number is 39.

Step-by-step explanation:

To solve this problem, we can set up a system of equations:

Let x represent the lesser number and y represent the greater number.

The sum of two numbers is 66, so we have the equation:

x + y = 66

Two times the lesser number is 15 more than the greater number, so we have the equation:

2x = y + 15

We can now solve this system of equations to find the values of x and y.

Substitute the value of y from the first equation into the second equation:

2x = (66 - x) + 15

Simplify:

2x = 81 - x

Add x to both sides:

3x = 81

Divide both sides by 3:

x = 27

Now substitute the value of x into the first equation:

27 + y = 66

Subtract 27 from both sides:

y = 39

So the lesser number (x) is 27 and the greater number (y) is 39.

Answer 2

See below!

Step-by-step explanation:

Let the two numbers be x and y

Condition # 1:

x + y = 66 ----------------(1)

Condition # 2:

2x = y + 15

2x - y = 15 ---------------(2)

Add both equations

x + y + 2x - y = 66 + 15

x + 2x = 66 + 15

3x = 81

Divide both sides by 3

x = 27

Put x = 27 in Eq. 1

27 + y = 66

Subtract 27 to both sides

y = 66 - 27

y = 39

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