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Two balls of clay are thrown and perfectly collide with each other. One ball of clay had mass of 42.9kg and a velocity of 58 m/s. The other ball of clay had a mass of 99.4 kg and an unknown velocity before the collision. If the velocity of the combined object was -38.6m/s after the collision. What was the velocity of the second clay ball before the collision?

Two objects have a perfectly elastic collision The first object has a mass of 34.2 kg and a velocity of 65.5m/s before the collision. The second object had a mass of 97.9kg and a velocity of -29.7 m/s before the collision. If the first object's velocity was -75.61m/s after the collision, what was the second objects velocity after the collision?

Two balls of clay are thrown and perfectly collide with each other. One ball of clay-example-1
User Catherin
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2 Answers

6 votes

Final answer:

The velocity of the second clay ball before the collision was -71.16 m/s. The velocity of mass B after the collision was -40.38 m/s.

Step-by-step explanation:

For question 1:

To find the velocity of the second clay ball before the collision, we can use the law of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision. We can express this as:

Mass1 * Velocity1 + Mass2 * Velocity2 = (Mass1 + Mass2) * Velocity after

Plugging in the values, we get:

(42.9 kg * 58 m/s) + (99.4 kg * Velocity2) = (42.9 kg + 99.4 kg) * -38.6 m/s

Solving for Velocity2, we find that the velocity of the second clay ball before the collision was -71.16 m/s.

For question 2:

We can use the same approach as in question 1 to find the velocity of mass B after the collision. The total momentum before the collision is equal to the total momentum after the collision, and we can express this as:

Mass A * Velocity A + Mass B * Velocity B = (Mass A + Mass B) * Velocity after

Plugging in the values, we get:

(34.2 kg * 65.5 m/s) + (97.9 kg * -29.7 m/s) = (34.2 kg + 97.9 kg) * -75.61 m/s

Solving for Velocity B, we find that the velocity of mass B after the collision was -40.38 m/s.

User Abhimuralidharan
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3.4k points
5 votes

Answer:

19.59m/s

Step-by-step explanation:

Using the law of conservation of linear momentum,

Total momentum before collision is equal to the Total momentum after collision.

Two balls of clay are thrown and perfectly collide with each other. One ball of clay-example-1
User Balsick
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3.2k points