Question

A ball is thrown vertically upwards with a speed of 10.0 m/s. At the moment the it reaches its maximum position what is its acceleration?​

Answer 1

10 m/s^2

Step-by-step explanation:

Third equation of motion:

`v^2=u^2-2gh`

`0=u^2-2g(h/2)\\h=(u^2)/(g) =(10^2)/(10)= 10m`

(How high it rises)

The acceleration would be 10 m/s^2