Question

A sack of sugar has more than 50KG and a density of 1610KG/m³. What is the volume?​

Answer 1

`{\boxed {{\sf \: v = 0.031 \\ \\ \\ {m}^(3) \\ \\ \: \\ \\ }}}`

Step-by-step explanation:

Cheers

Starting from the formula to determine the density, which states that:

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\sfρ = (m)/(v)}`

We clear v:

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\sf \: v = (m)/(ρ)}`

`\sf \: m→ 50kg \\ \sf ρ→ 1610kg/m³ \ \\\sf v→ ?`

Based on this data, you can plug it into the formula.

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\sf \: v = \frac{50kg}{1610kg/ {m}^(3) }}`

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: v = 0.031 {m}^(3)`

The alpha.