Question

A spinner has the numbers 11-20 on it. What is the probability that it will land on a multiple of 3?

Answer 1

`P(A) = (3)/(10)`

Explanation:

Given

`S = \{11,12,13,14,15,16,17,18,19,20\}`

Required

The probability of having a multiple of 3

Let the event of having a multiple of 3 be represented as: A

So:

`A = \{12,15,18\}`

`n(A) = 3`

So, the probability is:

`P(A) = (n(A))/(n(S))`

Where

`n(S) = 10` i.e. the sample size

So:

`P(A) = (n(A))/(n(S))`

`P(A) = (3)/(10)`