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A collection of nickels, dimes, and quarters consist of 14 coins with a total of $1.75. If the number of dimes is

equal to the number of nickels, find the number of each type of coins.

There are __nickels, __ dimes, and ___ quarters.

User Fjh
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1 Answer

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Answer:

There are 5 nickles, 5 dimes, and 4 quarters.

Explanation:

Pre-Solving

We are given that someone has a collection of nickles, dimes, and quarters, and they have 14 coins that equal to $1.75.

We also know that the number of dimes is equal to the number of nickles.

We want to find the number of each of the different types of coins.

Solving

Defining the Variable

Since we know that the number of dimes is the same as the number of nickles, if there are x dimes, then there should also be x nickles.

The number of the quarters would be the total - (number of nickles + number of dimes).

Since the total is 14, and the number of dimes and nickles is both x, the number of quarters will be:

14 - (x + x), or 14-2x

Here is what we have so far:

x = dimes

x = nickles

14-2x = quarters

Equation

Remember that the coins add up to $1.75 in value.

This means that x dimes will be $0.10x in value, x nickels will be $0.05x, and 14-2x quarters will be $0.25(14-2x) in value.

We can add these up all together:

0.10x + 0.05x + 0.25(14-2x) = 1.75

Solution

We can clear the decimals by multiplying everything by 100:

10x + 5x + 25(14-2x) = 175

Multiply.

10x + 5x + 350 - 50x = 175

Combine like terms.

-35x + 350 = 175

Subtract 350 from both sides.

-35x = -175

Divide both sides by -35.

x = 5

This means that there will be 5 nickles and 5 dimes.

Remember that the number of quarters is 14-2x; we can plug 5 in for x to get 14-2(5) = 14-10=4 quarters.

User Parks
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