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Solve the equation for all values of x by completing the square. x^2 - 11 = -4x

User Fel
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1 Answer

7 votes

Answer:


x=-2-√(15)\\\\x=-2+√(15)

Explanation:

Given equation:


x^2-11=-4x

Collect the terms in x on the left side and the constant on the right side of the equation:


\implies x^2-11+4x=-4x+4x


\implies x^2+4x-11=0


\implies x^2+4x-11+11=0+11


\implies x^2+4x=11

Add the square of half the coefficient of x to both sides of the equation:


\implies x^2+4x+\left((4)/(2)\right)^2=11+\left((4)/(2)\right)^2


\implies x^2+4x+4=11+4


\implies x^2+4x+4=15

Factor the perfect trinomial on the left side of the equation:


\implies (x+2)^2=15

Square root both sides:


\implies √((x+2)^2)=√(15)


\implies x+2=\pm√(15)

Subtract 2 from both sides:


\implies x+2-2=\pm√(15)-2


\implies x=-2\pm√(15)

Therefore, the solutions are:


x=-2-√(15), \;\; x=-2+√(15)

User LinX
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