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A scuba diver is 15.5 feet below the surface of the water. If the diver continues to swim downward at a rate of 2.5 feet per second, what is her location, in feet, relative to the surface after 712 seconds? feet

A scuba diver is 15.5 feet below the surface of the water. If the diver continues-example-1
User Noddy Cha
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2 Answers

6 votes
33! hope this helped
User Totowtwo
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The answers is: 33

33 is the integer that represents her location relative to the surface after 7 seconds.

And 33 feet far the diver have to go to return to the surface.

Explanation:

Given:

A scuba diver is 15.5 feet below the surface of the water.

The diver continues to swim downward at a rate of 2.5 feet per second.

Now, to find the integer represents her location relative to the surface after 7 seconds.

And to find how far does the diver have to go to return to the surface.

So, to get the integer represents her location relative to the surface after 7 seconds.

Initial depth = 15.5 feet.

Distance traveled down = 7 × 2.5 = 17.5 feet.

Final depth of water surface = Initial depth + Distance traveled down.

Final depth of water surface = 15.5 feet + 17.5 feet.

Final depth of water surface = 33 feet.

Thus, 33 is the integer represents her location relative to the surface after 7 seconds.

Now, to get how far does the diver have to go to return to the surface:

As, the diver goes to 33 feet down to the surface.

Thus, the diver to return she have to go through the same distance.

So, to return to the surface she need to go to 33 feet far.

Therefore, 33 is the integer that represents her location relative to the surface after 7 seconds.

And 33 feet far the diver have to go to return to the surface.

User Knocked Loose
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