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The average of 3 different positive integers a, b and c is 50. If a < b < c and b=30, what is the least possible value of c?

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Answer:

61

Explanation:

If the average of 3 different positive integers, a, b and c, is 50 then:


\implies (a+b+c)/(3)=50

If b = 30:


\implies (a+30+c)/(3)=50


\implies a+30+c=150


\implies a+c=120

If a < b < c then the least possible value of c is one more than the average of a + c.

Average of a + c:


\implies (a+c)/(2)=(120)/(2)


\implies (a+c)/(2)=60

So the least possible value of c is 60 + 1 = 61.

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