Question

Caroline has a unique pet chimpanzee that is relatively likely to have twins. Each pregnancy is independent, and

Caroline's chimpanzee has a 60% chance of having 1 baby and a 40% chance of having 2 babies each
pregnancy
If X is a random variable that represents the total number of chimpanzee babies if Caroline's chimpanzee gets
pregnant twice, drag the bars to graph the probability distribution for all possible values of X.

Answer 1

Answer: 2=.36, 3=.48, 4=.16

Explanation:

If we let "S" represent 1 baby and "D" represent 2 babies, the sample space for the chimpanzee's 2 pregnancies is {SS, SD, DS, DD}.

We can find the probability of each possible outcome by multiplying the probability of the independent events leading to that outcome.

Outcomes:. Probability:

SS. .60 x .60 = .36

SD. .60 x .40 = .24

DS. .40 x .60 = .24

DD. .40x .40 =.16

Total. 1.00

Lastly group the similar outcomes. SD+DS= .48