Question

Pls help whith my dr frost maths it is really hard

Answer 1

y = 1/2 x - 2

Explanation:

y-0 = 1/2 (x-4)

y = 1/2 x - 2

Answer 2

`y=(1)/(2)x-2`

Explanation:

`\boxed{\begin{minipage}{6.3 cm}\underline{Point-gradient form of a linear equation}\\\\$y-y_1=m(x-x_1)$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the gradient. \\ \phantom{ww}$\bullet$ $(x_1,y_1)$ is a point on the line.\\\end{minipage}}`

Given:

• Gradient m = 1/2
• Point on the line (x₁, y₁) = (4, 0)

Substitute the given values into the formula:

`\implies y-y_1=m(x-x_1)`

`\implies y-0=(1)/(2)(x-4)`

`\implies y=(1)/(2)(x-4)`

`\implies y=(1)/(2)x-(4)/(2)`

`\implies y=(1)/(2)x-2`

Therefore, an equation of the line with gradient 1/2 and that passes through the point (4, 0) is:

`\boxed{y=(1)/(2)x-2}`