Question

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Answer 1

Given:

• masses = 50kg and 120kg
• distance between them = 10m
• Gravitational constant= 6.7*10-¹¹ Nm² kg-²

To find:-

• gravitational force between them.

Solution:-

As we know that,

F = G m m'/r²

where m and m' are masses and r is the distance between them. on substituting the respective values, we have,

F = 6.67 *10-¹¹ * 50 * 120 / 10² N

F = 402 * 10-¹¹ N

F = 4.02 * 10² * 10-¹¹N

F = 4.02 * 10-⁹ N

and we are done!

Answer 2

4.02 × 10⁻⁹ N

Step-by-step explanation:

Gravitational Force

`F=(G \cdot m_1 \cdot m_2)/(r^2)`

where:

• F = force of gravity.
• G = gravitational constant.
• m₁ = mass of one object.
• m₂ = mass of other object.
• r = distance between the centers of the two objects (in meters).

Given values:

• G = 6.7 × 10⁻¹¹ Nm² kg⁻²
• m₁ = 50 kg
• m₂ = 120 kg
• r = 10 m

Substitute the values into the formula and solve for F:

`\implies F=((6.7 * 10^(-11)) \cdot 50 \cdot 120)/(10^2)`

`\implies F=(40200* 10^(-11))/(100)`

`\implies F=402* 10^(-11)`

`\implies F=4.02* 10^(-9)\;\;\sf N`

Therefore, the force of gravitation between the two objects is:

• 4.02 × 10⁻⁹ N