Question

a 32.0kg sign is attached outside of a building by four vertical ropes. how much tension (in n) would be in each individual rope to keep the sign motionless?

Answer 1

the answer would be 78.4N worth of tension each.

Step-by-step explanation:

we know that the sign is motionless and all of the tensions are the same, so let us represent the system with newtons second law with the y-axis pointing upwards

`\sum F_y=4t-mg`

where t is the tension of one of the strings and m is the mass of the signpost. We know that the net force in the y direction is zero, so
`4t-mg=0\Rightarrow{t=(mg)/(4)=(32.0*9.8)/(4)=78.4}`