Final answer:
To estimate the proportion of voters for candidate A with a margin of error of 3% at a 95% confidence level, the minimum sample size needed is approximately 1067 registered voters.
Step-by-step explanation:
To determine the minimum sample size needed for estimating the population proportion p of voters who plan to vote for candidate A with a margin of error of 3%, one can use the sample size formula for a proportion:
\(n = (Z^2 * p * (1 - p)) / E^2\)
Where:
n is the sample size,
Z is the z-score
p is the estimated population proportion (from previous surveys or pilot studies),
E is the expected margin of error.
However, when p is unknown, a conservative estimate where p = 0.5 is used as it provides the maximum variance, thus the largest sample size. The formula becomes:
\(n = (1.96^2 * 0.5 * 0.5) / 0.03^2\)
Calculating this gives us:
\(n = (3.8416 * 0.25) / 0.0009\)
\(n = (0.9604) / 0.0009\)
\(n ≈ 1067\)
Therefore, the minimum sample size needed with a margin of error of 3% at a 95% confidence level is approximately 1067 registered voters.