how many moles of gas are in 30.0 l of a contained tube with a temperature of 300.k and pressure at 200. atm? use r

asked Apr 28, 2023 155k views

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Answer:

234.61 mol

Step-by-step explanation:

According to the Ideal Gas Law:

PV=nRT

P= 200 atm

V= 30.0 L

T= 300 K

R= 0.0821
((atm)(L))/((mol)(K))

n=(PV)/(RT)

$n=((200atm)(30.0L))/(0.0821((atm)(L))/((mol)(K))(300K))\\n=234.61 mol$

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