Question

Reduce the force F ij = + (2 5 ) kN to point A(2m,3m) that acts on point B( 3m,5m) - .

Answer 1

Given :

Force,
`\vec{F}= (2\hat{i} + 5\hat{j})\ kN`.

Force is acting at point A( 2 m, 3 m ) and B( 3 m, 5 m )

To Find :

The work done by force F .

Solution :

Displacement vector between point A and B is :

`\vec{d} = (3-2)\hat{i} + (5-3)\hat{j}\\\\\vec{d} = \hat{i} + 2\hat{j}`

Now, we know work done is given by :

`W = \vec{F}.\vec{d}\\\\W= (2\hat{i} + 5\hat{j}).(\hat{i}+\hat{2j})\\\\W = (2* 1) +( 5* 2) \ kJ\\\\W = 12 \ kJ`

W = 12000 J

Therefore, work done by force is 12000 J .