Question

what is the diffraction angle in degrees for a setup using a 6,393 angstrom slit with a minima of order 28 and a wavelength of 22 nm?

Answer 1

The diffraction angle can be calculated using the formula: sin(theta) = n * lambda / d, where n is the order of the minima, lambda is the wavelength of the light, and d is the width of the slit. Plugging in the values, the diffraction angle for this setup is 12.46 degrees.

Step-by-step explanation:

The diffraction angle can be calculated using the formula:

sin(theta) = n * lambda / d

Where:

• theta is the diffraction angle
• n is the order of the minima (in this case 28)
• lambda is the wavelength of the light (22 nm)
• d is the width of the slit (6,393 angstroms)

Plugging in the values:

sin(theta) = 28 * (22 x 10^-9 m) / (6,393 x 10^-10 m)

Solving for theta:

theta = arcsin(28 * 22 / 6,393) = 0.2172 radians

Converting radians to degrees:

theta = 0.2172 * (180 / pi) = 12.46 degrees