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Answer:
- y=x^2 parent function
- y=x^2
- vertex (minimum) at (0, 0); end behavior (-∞, ∞) and (∞, ∞)
Explanation:
1. You can call the graph whatever you like. Since you're graphing the parent function y=x², you might want that in the title.
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2. The problem statement tells us we're graphing y = x².
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3. The quadratic function has one turning point on the axis of symmetry. The turning point for the parent function is its vertex at (0, 0). This point is a minimum, because the parent function has a positive coefficient.
The function is even degree with a positive leading coefficient, so the end behavior tends to +∞ for x going to either -∞ or +∞.
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Additional comment
If we're to "refer to the previous slide", it would be nice to be able to see that slide. As is, we're guessing at what the question is really after. The basic y=x^2 function will have been studied first thing when nonlinear polynomials are introduced. This should all be very elementary stuff.