−9≤32z−3≤3 Write the solution using interval notation.

asked Sep 6, 2023 164k views

1 vote

−9≤32z−3≤3
Write the solution using interval notation.

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4 votes

Answer:

$z \in \left[-(3)/(16), (3)/(16) \right]$

Explanation:

$-9 \leq 32z-3 \leq 3 \\ \\ -6 \leq 32z \leq 6 \\ \\ -(3)/(16) \leq z \leq (3)/(16) \\ \\ \therefore z \in \left[-(3)/(16), (3)/(16) \right]$

MouzmiSadiq answered Sep 11, 2023

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