Question

A sample of helium gas in a balloon is compressed from 5. 26 l to 3. 78 l at constant temperature. If the initial pressure was 4. 39 atm, what is the new pressure?.

Answer 1

`P_2=3.79atm`

Step-by-step explanation:

According to Boyle's Law:

`P_1V_1=P_2V_2`

Rewriting to find
`P_2`:

`P_2=(P_1V_1)/(V_2)`

`P_1=4.39atm\\V_1=5.26L\\V_2=3.78\\P_2=((4.39atm)(3.26L))/(3.78L)\\P_2=3.7861atm`

This answer follows Boyle's statement that pressure is inversely proportional to volume (V∝
`(1)/(P)`). As the volume decreases, the pressure must proportionately increase.