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How much pressure (absolute) must a submarine withstand at a depth of 120. 0 m in the ocean?.

User Xarus
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Answer:

Step-by-step explanation:

Given:

ρ = 1 030 kg/m³ - Salt water density

h = 120.0 m - Submergence depth of the submarine

_____________________________

p - ?

Pressure:

p = ρ·g·h

p = 1030·9.8·120.0 ≈ 12·10⁶ Pa or p = 12 MPa

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