Answer:
ΔNOP is obtuse triangle and isosceles triangle.
Explanation:
An acute triangle has three angles that each measure less than 90°.
An obtuse triangle is a triangle with one angle greater than 90°.
A right triangle is a triangle with one 90° angle represented by the symbol ∟.
From inspection of the triangle, it appears that angle P is greater than 90°, which means it is an obtuse triangle.
This can be confirmed by using the cosine rule to calculate angle P.
![\boxed{\begin{minipage}{7.6 cm}\underline{Cosine Rule (for finding angles)} \\\\$\cos(C)=(a^2+b^2-c^2)/(2ab)$\\\\\\where:\\ \phantom{ww}$\bullet$ $C$ is the angle. \\ \phantom{ww}$\bullet$ $a$ and $b$ are the sides adjacent the angle. \\ \phantom{ww}$\bullet$ $c$ is the side opposite the angle.\\\end{minipage}}](https://img.qammunity.org/2023/formulas/mathematics/college/5l5bl1gj00w03ibky528v2fwt4cbwsm3zn.png)
Therefore:
![\implies \cos(P)=(4^2+4^2-7^2)/(2(4)(4))](https://img.qammunity.org/2023/formulas/mathematics/college/vsfdf4ky463qmfuz04bpxxmdxgnukcj69j.png)
![\implies \cos(P)=-(17)/(32)](https://img.qammunity.org/2023/formulas/mathematics/college/9g33m9np7157nqbg8xfs12xn5ikrzwb1qi.png)
![\implies P=\cos^(-1)\left(-(17)/(32)\right)](https://img.qammunity.org/2023/formulas/mathematics/college/3nq1079fi2vpcqfwh5gbux4lxqnaqae9ee.png)
![\implies P=122.08995...^(\circ)](https://img.qammunity.org/2023/formulas/mathematics/college/1amyg1735yz2qavw1k6grtqgzhnxrr865d.png)
As 122.1° > 90°, this proves that triangle NOP is obtuse.
An equilateral triangle has three sides of equal length.
A scalene triangle has three sides of differing lengths.
An isosceles triangle has two sides of equal length.
Therefore, as NP = OP ≠ ON, the triangle has two sides of equal length and so it an isosceles triangle.