Complete question :
At a certain bus station, 47% of all arrivals are late. Suppose a random
sample of 12 bus arrivals is examined. Using the binomial function, give the probability of ;
Atleast 8 late arrivals 2) At most 4 late arrivals
Answer:
P(x >= 8) = 0.1411 ;
P(x ≤ 4) = 0.2570
Explanation:
Using the binomial probability distribution relation :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
p = 47% = 0.47
1 - p = 0.53
n = 12
A.)
Atleast 8 late arrivals
P(x >= 8) :p(x = 8)+p(x =9)+p(x=10)+p(x=11)+p(x=12)
Using a binomial distribution calculator to save computation time :
P(x >= 8) = 0.141096
P(x >= 8) = 0.1411
B.)
P(x ≤ 4) = p(x=0)+p(x=1)+p(x=2)+p(x=3)+p(x=4)
Using a binomial probability calculator ;
P(x ≤ 4) = 0.25697
P(x ≤ 4) = 0.2570