Question

How far does an object fall down after 2 seconds if it is initially at rest?.

Answer 1

19.6 m

Step-by-step explanation:

Start with the physics distance formula

df = do + vo t + 1/2 a t^2

do = original position = 0 vo = origianl velocity = 0 (starts at rest)

so this becomes d = 1/2 a t^2

= 1/2 ( 9.81 m/s^2) (2 s)^2 = 19.6 m