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√ 4(x+5)² - 130 = 0 , please solve ​

User Tkazik
by
5.3k points

1 Answer

2 votes

Answer:

x = 60, -70

Explanation:

Let's move the constant (-130) to the right by adding it to both sides.



√(x) 4(x+5)^(2) =130

Now, we can rewrite the equation as (since the square root and square cancel):
2 × | x + 5 | = 130

To get rid of the 2 multiplication, we can divide both sides by 2:

| x + 5 | = 65

This leaves us with 2 equations:

x + 5 = 65

x + 5 = -65

Simplify.

x1 = 60

x2 = -65

User Parag Meshram
by
4.9k points