Question

1. If a truck tire holds 25.0 liters of air at 25.0°C, what will be the volume of air in the tire if the temperature

increases to 30.0 C

Answer 1

25.4 L

Explanation:

Charles's Law

`\sf (V_1)/(T_1)=(V_2)/(T_2)\quad \textsf{(when pressure is constant and temperature is in kelvin)}`

where:

• V₁ = first volume.
• T₁ = first temperature.
• V₂ = second volume.
• T₂ = second temperature.

Given:

• V₁ = 25 L
• T₁ = 25.0 °C
• T₂ = 30.0 °C

Convert Celsius to kelvin.

Kelvin = Celsius + 273.15

`\implies \sf T_1= 25 + 273.15 = 298.15 \;K`

`\implies \sf T_2 = 30 + 273.15 = 303.15\; K`

Substitute the given values into the formula:

`\implies \sf (25)/(298.15)=(V_2)/(303.15)`

`\implies \sf V_2 =303.15 \cdot (25)/(298.15)`

`\implies \sf V_2 =(7478.75)/(298.15)`

`\implies \sf V_2 =25.41925205...L`

Therefore, the volume of air in the tire if the temperature increases to 30.0 °C is 25.4 L (nearest tenth).