Question

What is the energy change per gram of ice when an iceberg composed of pure water, cp = 2.06 j/(gk, is heated from -25°c to -15°c?

Answer 1

`Q=20.6(J)/(g)`

Step-by-step explanation:

Hello there!

In this case, according to the equation for the calculation of the heat during a heating process:

`Q=mC(T_f-T_i)`

It is possible to compute it per gram of ice by just removing m from the equation by dividing at both sides. Next we plug in the given specific heat and the final and initial temperatures to obtain:

`Q=2.06(J)/(g\°C)[-15\°C-(-25\°C)] \\\\Q=20.6(J)/(g)`

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