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Suppose f(x)=√x+1 and g(x)=x² + n. If f(g(7)) = 9, what is the value of g(n)?
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1 Answer

5 votes

Explanation:

g(7)=


{7}^(2) + n


49 + n

f(g(7))=n


f(g(7)) = √(49 + n + 1)


f(g(7)) = √(n + 50)


9 = √(n + 50)


81 = n + 50


n = 31

So


g(31) = 31 {}^(2) + 31


= 992

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