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if the temperature of a blackbody is 2700 k, at what wavelength, in units of nanometers, does it radiate the most energy?

User Jorgebg
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1 Answer

5 votes

Answer:

Wavelength = 1074 nm

Step-by-step explanation:

Given:

T = 2700 K

b = 2.9·10⁻³ m·K - Wine's constant

___________

λm - ?

Wine Law:

λm = b / T

λm = 2.9·10⁻³ / 2700 ≈ 1074·10⁻⁹ m or λm = 1074 nm

User Ill
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