Question

A spring has a spring constant of 53 N/m. How much elastic potential energy is stored in the spring when it is compressed by 0.21 m?

A. 2.33 J
B. 5.57 J
C. 11.1 J
D. 1.17 J​

Answer 1

Answer1.17:

Step-by-step explanation:

Answer 2

D. 1.17 J

Step-by-step explanation:

The potential energy stored in a spring is given by the following:

U = (K•x²)/2

U -> elastic Potential energy

K -> spring constant

x -> compression

So:

U = (53•0.21²)/2

U = 1.17