Question

Part A: If (6²)x = 1, what is the value of x? Explain your answer. (5 points)

Part B: If (6ˆ0)x = 1, what are the possible values of x? Explain your answer. (5 points)

Answer 1

`\\ \tt\hookrightarrow 6^2x=1`

`\\ \tt\hookrightarrow 36x=1`

`\\ \tt\hookrightarrow x=1/36`

#Part-B

`\\ \tt\hookrightarrow 6^0x=1`

• a^0=1

`\\ \tt\hookrightarrow x=1`

Answer 2

A: x = 1/36

B: x = 1

Explanation:

Part A:

(6²)x = 1

6² = 36, so we write 36 instead of 6² and get:

36x = 1

Now we divide both sides by 36 to find the value of x.

x = 1/36

Part B:

(6ˆ0)x = 1

6^0 = 1, so we replace 6^0 with 1 in the equation and get:

1x = 1

1x is the same as x, so our solution is:

x = 1