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Find the equation of a line that passes through the point (5,3) and has a gradient of -2. Leave your answer in the form = mx + c y=​

User SWalters
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(\stackrel{x_1}{5}~,~\stackrel{y_1}{3})\hspace{10em} \stackrel{slope}{m} ~=~ - 2 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{- 2}(x-\stackrel{x_1}{5}) \\\\\\ y-3=-2x+10\implies {\Large \begin{array}{llll} y=-2x+13 \end{array}}

User Math Chiller
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