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what is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.14?
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what is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.14?

User Searle
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4 votes

Answer:7.056 m/s²

Explanation: Resultant force = g - μmg

ma = g - μmg

a = g(1 - 2μ) / 2

a = 7.056 m/s²

User Poliane Brito
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