Question

an object is thrown downward from the top of a 100 m cliff. the object is thrown with an initial velocity of 5 m/s. how long does it take for the object to reach the ground?

Answer 1

4.0 s

Step-by-step explanation:

d =- 100

vo = -5

a = - 5

d = vo t + 1/2 a t^2

-100 = - 5t + 1/2 (-9.81)t^2

4.905 t^2 + 5t -100 = 0

Use quadratic Formula a = 4.905 b = 5 c=-100 to find t = 4.0 s