Question

What is the speed of a 200-kilogram car that is driving with 2000 joules of kinetic energy? (SHOW ALL WORK)

Answer 1

v ≈ 4.47

Step-by-step explanation:

The Formula needed = KE =
`(1)/(2)` m v²

Substitute with numbers known:

2000J =
`(1)/(2)` × 200kg × v²

Simplify:

÷100 ÷100 (Divide by 100 on both sides)

2000J = 100 × v²

`(2000J)/(100)` = v²

20 = v²

√ √ (Square root on both sides)

√20 = √v²

4.472135955 = v (Round to whatever the question asks)

v ≈ 4.47 (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)