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A softball player is running at 4.88 m/sec when she slides into second base coming to a stop in .872 seconds. How far did she slide, and what was her acceleration?​
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A softball player is running at 4.88 m/sec when she slides into second base coming to a stop in .872 seconds. How far did she slide, and what was her acceleration?​

User Anice Jahanjoo
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1 Answer

20 votes
20 votes

Answer:

d=v1t - .5at^2

d=4.88 x .872 - 0.5 x (4.88/0.872) x 0.872^2

d=4.255 - 2.12

d= 2.135m

Step-by-step explanation:

acceleration is negative because she is slowing down.

User Jakub Lortz
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