Please help im close to failing it would mean the world

Bruiser asked Nov 7, 2023

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4 votes

Bruiser asked Nov 7, 2023

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14 votes

$\\ \rm\hookrightarrow (3^8.2^(-5))^(-2)(2^(-2)3^(-3))^4.3^(28)$

$\\ \rm\hookrightarrow 3^(-16)</p><p>.2^(-10).2^(-8).3^(-12)>3^(28)$

$\\ \rm\hookrightarrow 3^(-16-12+28)2^(-10-8)$

$\\ \rm\hookrightarrow 3^02^(-18)$

$\\ \rm\hookrightarrow (1)/(2^(18))$

IT Hit WebDAV answered Nov 12, 2023

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