Question

A) If 2 sin 0 = √√3 and 0° ≤ 0 ≤ 90° then find 0.

Answer 1

Θ = 60°

Explanation:

2sinΘ =
`√(3)` ( divide both sides by 2 )

sinΘ =
`(√(3) )/(2)` , then

Θ =
`sin^(-1)` (
`(√(3) )/(2)` ) = 60°