Question

Data Collection

Mass of the original sample of mixture (g) 1.558
Mass of recovered naphthalene (g) 0.483
Mass of recovered 3-nitroaniline (g) 0.499
Mass of recovered benzoic acid (g) 0.467
Calculations:
a. % by mass of naphthalene in original sample.
b. % by mass of 3-nitroaniline in original sample.
c. % by mass of benzoic acid in original sample.
d. total percent recovered.

Answer 1

For a): The mass percent of naphthalene in the original sample is 31.00 %.

For b): The mass percent of 3-nitroaniline in the original sample is 32.03 %.

For c): The mass percent of benzoic acid in the original sample is 29.97 %.

For d): The total percent recovered is 93.00 %.

Step-by-step explanation:

Percentage by mass is defined as the ratio of the mass of a substance to the mass of the solution multiplied by 100. The formula used for this is:

`\text{Percent by mass}=\frac{\text{Mass of substance}}{\text{Mass of a solution}} * 100` ......(1)

a):

Mass of naphthalene = 0.483 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

`\%\text{ mass of naphthalene}=(0.483 g)/(1.558)* 100\\\\\%\text{ mass of naphthalene}=31.00 \%`

b):

Mass of 3-nitroaniline = 0.499 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

`\%\text{ mass of 3-nitroaniline}=(0.499 g)/(1.558)* 100\\\\\%\text{ mass of 3-nitroaniline}=32.03 \%`

c):

Mass of benzoic acid = 0.467 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

`\%\text{ mass of benzoic acid}=(0.467 g)/(1.558)* 100\\\\\%\text{ mass of benozic acid}=29.97 \%`

d):

Total mass recovered = [0.483 + 0.499 + 0.467] = 1.449 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

`\text{Total percent recovered}=(1.449 g)/(1.558)* 100\\\\\text{Total percent recovered}=93.00\%`